PyPE solution to PE problem 48
Registered by
Scott Armitage
PyPE solution to PE problem 48
Blueprint information
- Status:
- Complete
- Approver:
- None
- Priority:
- Undefined
- Drafter:
- None
- Direction:
- Needs approval
- Assignee:
- None
- Definition:
- Approved
- Series goal:
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- Implementation:
-
Implemented
- Milestone target:
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- Started by
- Scott Armitage
- Completed by
- Scott Armitage
Whiteboard
ProjectEule
===
The series, 1^(1) + 2^(2) + 3^(3) + ... + 10^(10) = 10405071317.
Find the last ten digits of the series,
1^(1) + 2^(2) + 3^(3) + ... + 1000^(1000).
Solution
--------
Brute force.
Answer
------
9110846700
(?)
