PyPE solution to PE problem 38

Registered by Scott Armitage

PyPE solution to PE problem 38

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Scott Armitage
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Scott Armitage

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    ProjectEuler.net problem 38
    ===========================

    Take the number 192 and multiply it by each of 1, 2, and 3:

        192 * 1 = 192
        192 * 2 = 384
        192 * 3 = 576

    By concatenating each product we get the 1 to 9 pandigital, 192384576. We
    will call 192384576 the concatenated product of 192 and (1,2,3)

    The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4,
    and 5, giving the pandigital, 918273645, which is the concatenated product
    of 9 and (1,2,3,4,5).

    What is the largest 1 to 9 pandigital 9-digit number that can be formed as
    the concatenated product of an integer with (1,2, ... , n) where n > 1?

    Solution
    --------

    This is a brute force solution.

    Answer
    ------

    932718654

(?)

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